C++ Institute CPP - C++ Certified Professional Programmer

What happens when you attempt to compile and run the following code?

#include

#include

using namespace std;

int main() {

int t[] = { 1, 1, 2, 2, 3, 3, 4, 4, 5, 5 };

string s[] = { "one", "one", "two", "two", "three","three", "four", "four", "five", "five"};

map m;

for (int i = 0; i < 10; i++) {

m.push_back(pair(t[i], s[i]));

}

for (map::iterator i = m.begin(); i != m.end(); i++) {

cout << i?>first << " ";

}

return 0;

}

What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

int main () {

int t[] = {1,2,3,2,3,5,1,2,7,3,2,1,10, 4,4,5};

vector v (t,t+15);

vector::iterator it = search_n(v.begin(), v.end(), 4, 2);

cout<< it?v.begin()<

return 0;

}

Program outputs:

What happens when you attempt to compile and run the following code? Choose all that apply.

#include

#include

#include

#include

#include

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) {out<

int main () {

int t[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};

fstream f("test.out", ios::trunc|ios::out);

list l(t, t+10);

for_each(l.begin(), l.end(), Out(f));

f.close(); f.open("test.out");

for( ; f.good() ; ) {

int i; f>>i;

cout<

}

f.close();

return 0;

}

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<

int main() {

int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3};

deque d1(t, t+10);

set s1(t,t+10);

cout<

return 0;

}

Choose all possible outputs (all that apply):

What happens when you attempt to compile and run the following code?

#include

using namespace std;

template

void f(A a)

{

cout<<1<

}

void f(int a)

{

cout<<2<

}

int main()

{

int a = 1;

f(a);

return 0;

}

What happens when you attempt to compile and run the following code?

#include

using namespace std;

int main()

{

cout.setf(ios::hex, ios::basefield);

cout<<100<<" ";

cout.flags(ios::showbase);

cout<<100<<" ";

return 0;

}

Program outputs:

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

#include

using namespace std;

int main(){

int t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };

vector v(t, t+10);

map m;

for(vector::iterator i=v.begin(); i!=v.end(); i++) {

stringstream s; s<<*i<<*i; m.insert(pair(*i,s.str()));

}

for(map::iterator i=m.begin();i!= m.end(); i++) {

cout<<*i<<" ";

}

return 0;

}

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

#include

using namespace std;

int main()

{

int t[] ={ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10};

deque mydeck(t, t+10);list mylist(t,t+10);

queue first;

queue second(mydeck);

queue third(second);

queue > fourth(mylist);

mylist.clear();third.clear();

cout<

cout<

return 0;

}

What happens when you attempt to compile and run the following code?

#include

#include

using namespace std;

template

void print(T start, T end) {

while (start != end) {

std::cout << *start << " "; start++;

}

}

int main()

{

int t1[] ={ 1, 7, 8, 4, 5 };

list l1(t1, t1 + 5);

int t2[] ={ 3, 2, 6, 9, 0 };

list l2(t2, t2 + 5);

l1.sort();

list::iterator it = l2.begin();

it++; it++;

l1.splice(l1.end(),l2, it, l2.end());

print(l1.begin(), l1.end()); cout<<"Size:"<

print(l2.begin(), l2.end()); cout<<"Size:"<

return 0;

}

What happens when you attempt to compile and run the following code?

#include

#include

using namespace std;

template

class A {

T_v;

public:

A() {}

A(T v): _v(v){}

T getV() { return _v; }

void add(T & a) { _v+=a; }

void add(string & a) {

_v.insert(0, a);

}

};

int main()

{

Aa("Hello");

string s(" world!");

a.add(s);

cout << a.getV() <

return 0;

}