C++ Institute CPP - C++ Certified Professional Programmer

What happens when you attempt to compile and run the following code?

#include

using namespace std;

void g(int a)

{

cout<

}

template

void g(A a)

{

cout<

}

int main()

{

int a = 1;

g(a);

return 0;

}

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<

int main() {

int t[]={3,2,4,1,5,6,10,8,7,9};

vector v1(t, t+10);

for_each(v1.begin(), v1.end(), bind2nd(plus(), 1));

for_each(v1.rbegin(), v1.rend(), Out(cout));cout<

return 0;

}

Program outputs:

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

using namespace std;

void myfunction(int i) {

cout << " " << i;

}

int main() {

int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };

set s1(t, t+10);

vector v1(s1.rbegin(), s1.rend());

swap_ranges(s1.begin(), s1.end(), v1.begin());

for_each(v1.begin(), v1.end(), myfunction);

for_each(s1.begin(), s1.end(), myfunction);

return 0;

}

Program outputs:

What will happen when you attempt to compile and run the code below, assuming that file test.in contains the following sequence: 1 2 3?

#include

#include

#include

#include

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) {out<

int main () {

ifstream f("test.in");

list l;

for( ; f.good() ; ) {

int i;

f>>i;

l.push_back(i);

}

f.close();

for_each(l.begin(), l.end(), Out(cout));

return 0;

}

Program will output:

What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

class B { int val;

public:

B(int v):val(v){}

int getV() const {return val;} bool operator < (const B & v) const { return val

ostream & operator <<(ostream & out, const B & v) { out<

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<

int main() {

B t1[]={3,2,4,1,5};

B t2[]={6,10,8,7,9};

vector v1(10);

sort(t1, t1+5);

sort(t2, t2+5);

merge(t1,t1+5,t2,t2+5,v1.begin());

for_each(v1.begin(), v1.end(), Out(cout));cout<

return 0;

}

Program outputs: